\(a,2\dfrac{3}{5}=2,6\\ 2,4< 2,6\\ =>2,4< 2\dfrac{3}{5}\\ b,-\dfrac{2}{5}=-0,4\\ -0,12>-0,4\\ =>-0,12>-\dfrac{2}{5}\\ c,-\dfrac{2}{7}=-0,285>-0,3\\ =>-\dfrac{2}{7}>-0,3\)
a)
\(2,4=\dfrac{12}{5},2\dfrac{3}{5}=\dfrac{13}{5}=>\dfrac{12}{5}< \dfrac{13}{5}=>2,4< 2\dfrac{3}{5}\)
b)
\(-0,12=-\dfrac{3}{25},-\dfrac{2}{5}=-\dfrac{10}{25}=>-\dfrac{3}{25}>-\dfrac{10}{25}=>-0,12>-\dfrac{2}{5}\)
c)
\(-0,3=-\dfrac{3}{10}=-\dfrac{21}{70},-\dfrac{2}{7}=-\dfrac{20}{70}=>-\dfrac{20}{70}>-\dfrac{21}{70}=>-\dfrac{2}{7}>-0,3\)