\(\dfrac{1}{4}+\dfrac{3}{4}\left(-\dfrac{1}{2}+\dfrac{2}{3}\right)\)
\(=\dfrac{1}{4}+\dfrac{3}{4}\left(\dfrac{4}{6}-\dfrac{3}{6}\right)\)
\(=\dfrac{1}{4}+\dfrac{3}{4}.\dfrac{1}{6}\)
\(=\dfrac{2}{8}+\dfrac{1}{8}\)
\(=\dfrac{3}{8}\)
\(=\dfrac{1}{4}+\dfrac{3}{4}\cdot\dfrac{-3+4}{6}=\dfrac{1}{4}+\dfrac{3}{4}\cdot\dfrac{1}{6}\)
=1/4+1/8
=3/8
\(\dfrac{1}{4}+\dfrac{3}{4}.\left(-\dfrac{1}{2}+\dfrac{2}{3}\right)=\dfrac{1}{4}+\dfrac{3}{4}.\left(-\dfrac{3}{6}+\dfrac{4}{6}\right)=\dfrac{1}{4}+\dfrac{3}{4}.\dfrac{1}{6}=\dfrac{1}{4}+\dfrac{1}{8}=\dfrac{2}{8}+\dfrac{1}{8}=\dfrac{3}{8}\)
