Question

Answer 1

`a, x^2 + 4x + 4 + 3 =0`

`-> (x+2)^2 + 3= 0 ->` Vô lý.

`b, -> (x + 51 + 49)/49 + (x + 52+48)/48 + (x-7 + 107)/107 = 0`

`-> (x+100)/49 + (x+100)/48 + (x+100)/107 = 0`

`-> (x+100)(1/49 + 1/48 + 1/107) = 0`

`-> x + 100 = 0`

`-> x = -100`

Answer 2

Giúp mình nhanh nhé! Cảm ơn các bạn

 

Answer 3

a: =>x²+4x+4+3=0

=>(x+2)^2+3=0(loại)

b: \(\Leftrightarrow\left(\dfrac{x+51}{49}+1\right)+\left(\dfrac{x+52}{48}+1\right)+\left(\dfrac{x-7}{107}+1\right)=0\)

=>x+100=0

=>x=-100