Question

Answer 1

`f(1) = 1 + 1^3 + .. + 1^101`

`= 1 + ... + 1 ( (101 - 1):2+1=51` số `)`

`= 51`

`f(-1) = 1 - 1^3 - 1^5 - ... - 1^101`

`= 1 - 1 - 1 - ... - 1 ( 50` số `-1 )`

`= -49`.

Answer 2

\(f\left(1\right)=1+1+...+1+1=51\)

\(f\left(-1\right)=1+\left(-1\right)+...+\left(-1\right)\)

\(=1-50=-49\)