\(\Leftrightarrow3^x\left(1+3^2\right)=270\)
\(\Leftrightarrow3^x=27\)
hay x=3
Ta có: \(3^x+3^{x+2}=270\)
\(\Rightarrow3^x+3^x.9=270\)
\(\Rightarrow3^x\left(1+9\right)=270\)
\(\Rightarrow3^x=27\Rightarrow x=3\)
\(\Rightarrow3^X+3^X.3^2=270\)
\(\Rightarrow3^X.\left(3^2+1\right)=270\)
\(\Rightarrow3^X.10=270\)
\(\Rightarrow3^X=27\)
\(\Rightarrow3^X=3^3\)
\(\Rightarrow x=3\)