Do \(sinx\le1\) nên \(y\le3.1+\dfrac{1}{2}=\dfrac{7}{2}\)
Dấu "=" xảy ra \(\Leftrightarrow\sin x=1\Leftrightarrow x=90^0\)
Vậy \(y_{max}=\dfrac{7}{2}\)
`y=3` `sin` `x+1/2`
Vì `-1` `<=` `sin` `x` `<=` `+` `1/2`
`=>-3` `<=` `3` `sin` `x` `=` `3`
`=>-5/2` `<=` `3` `sin` `x` `+` `1/2` `<=` `7/2`
`=>-5/2` `<=` `y` `<=` `7/2`
Vậy `max` `y` `=7/2`
Chọn `A`