Bài 2:
1: \(=4x^3-4x^2+4x-\left(4x^3-4x^2-x^2+x\right)\)
\(=4x^3-4x^2+4x-4x^3+5x^2-x=x^2+3x\)
Khi x=-4 thì \(A=\left(-4\right)^2+3\cdot\left(-4\right)=16-12=4\)
2: \(B=x^2+12x+35-\left(x^2-x-12\right)\)
\(=x^2+12x+35-x^2+x+12=13x+47\)
Khi x=-2 thì B=47-26=21