a) Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\widehat{A}+\widehat{B}+\widehat{C}+\widehat{D}=360^o\)
Do \(\dfrac{\widehat{A}}{4}=\dfrac{\widehat{B}}{3}=\dfrac{\widehat{C}}{2}=\dfrac{\widehat{D}}{1}=\dfrac{\widehat{A}+\widehat{B}+\widehat{C}+\widehat{D}}{4+3+2+1}\)
\(=\dfrac{360^o}{10}=36^o\)
\(\Rightarrow\left\{{}\begin{matrix}\widehat{A}=144^o\\\widehat{B}=108^o\\\widehat{C}=72^o\\\widehat{D}=36^o\end{matrix}\right.\)
Đúng 1
Bình luận (0)
