\(\dfrac{3}{x+3}=\dfrac{15}{55}\)
nên x+3=11
hay x=8
\(\dfrac{3}{x+3}=\dfrac{3}{11}\)
\(3:\left(x+3\right)=\dfrac{3}{11}\)
\(x+3=3:\dfrac{3}{11}\)
\(x+3=11\)
\(x=8\)
=> ( X + 3 ) x 15 = 3 x 55
=>( X + 3 ) x 15 = 165
=> X + 3 = 165 : 15
=> X + 3 = 11
=> X = 8
15/55 = 15 : 3 = 5, 55 : 5 = 11 - 3 = 8
\(\dfrac{3}{x+3}=\dfrac{15}{55}\\ \dfrac{3}{x+3}=\dfrac{3}{11}\)
`<=>(x+3)xx3=3xx11`
`(x+3)xx3=33`
`x+3=11`
`x=8`
Vậy `x=8`
`@An`