\(=\dfrac{1}{12}+\dfrac{8}{12}-\dfrac{9}{12}=0\)
\(=\dfrac{1}{12}+\dfrac{8}{12}-\dfrac{9}{12}=\dfrac{1+8-9}{12}=0\)
\(\dfrac{1}{12}+\dfrac{2}{3}-\dfrac{3}{4}=\dfrac{1}{12}+\dfrac{8}{12}-\dfrac{9}{12}=\dfrac{1+8-9}{12}=\dfrac{0}{12}=0\)
\(\dfrac{1}{12}+\dfrac{2}{3}+-\dfrac{3}{4}\)=\(\dfrac{1}{12}+\dfrac{8}{12}-\dfrac{9}{12}\)=\(0\)