f: \(\Leftrightarrow3\left(3x+2\right)-3x-1=12x+10\)
=>9x+2-3x-1=12x+10
=>6x+1=12x+10
=>-6x=9
hay x=-3/2
g: \(\Leftrightarrow30x-6\left(2x-5\right)+5\left(x+8\right)=210+10\left(x-1\right)\)
=>30x-12x+30+5x+40=210+10x-10
=>23x+70=10x+200
=>13x=130
hay x=10
i: \(x^2-5x+6=0\)
=>(x-2)(x-3)=0
=>x=2 hoặc x=3