Câu hỏi của Nguyễn Đức Hiển

Question

Nguyễn Việt Lâm · Accepted Answer

$P\left(x\right)+\left(x^3+2x^2+5x+\dfrac{1}{2}\right)=3x^3+3x^2+5x-\dfrac{1}{2}$$\Rightarrow P\left(x\right)=3x^3+3x^2+5x-\dfrac{1}{2}-\left(x^3+2x^2+5x+\dfrac{1}{2}\right)$$\Rightarrow P\left(x\right)=2x^3+x^2-1$Câu trả lời: $P\left(x\right)+\left(x^3+2x^2+5x+\dfrac{1}{2}\right)=3x^3+3x^2+5x-\dfrac{1}{2}$$\Rightarrow P\left(x\right)=3x^3+3x^2+5x-\dfrac{1}{2}-\left(x^3+2x^2+5x+\dfrac{1}{2}\right)$$\Rightarrow P\left(x\right)=2x^3+x^2-1$

Nguyễn Ngọc Huy Toàn · Answer

$P\left(x\right)=3x^3+3x^2+5x-\dfrac{1}{2}-\left(x^3+2x^2+5x+\dfrac{1}{2}\right)$$P\left(x\right)=3x^3+3x^2+5x-\dfrac{1}{2}-x^3-2x^2-5x-\dfrac{1}{2}$$P\left(x\right)=2x^3+x^2-1$Câu trả lời: $P\left(x\right)=3x^3+3x^2+5x-\dfrac{1}{2}-\left(x^3+2x^2+5x+\dfrac{1}{2}\right)$$P\left(x\right)=3x^3+3x^2+5x-\dfrac{1}{2}-x^3-2x^2-5x-\dfrac{1}{2}$$P\left(x\right)=2x^3+x^2-1$

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