\(c,\dfrac{x+1}{4}-\dfrac{x}{5}=\dfrac{x}{6}\)
\(\Leftrightarrow15\left(x+1\right)-12x=10x\)
\(\Leftrightarrow15x+15-12x=10x\)
\(\Leftrightarrow15x-12x-10x=-15\)
\(\Leftrightarrow-7x=-15\)
\(\Leftrightarrow x=\dfrac{15}{7}\)
Vậy \(S=\left\{\dfrac{15}{7}\right\}\)
Đúng 3
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\(\dfrac{x+1}{4}-\dfrac{x}{5}=\dfrac{x}{6}\)
\(\dfrac{\left(x+1\right).5.6}{4.5.6}-\dfrac{x.4.6}{5.4.6}=\dfrac{x.5.4}{6.5.4}\)
\(\dfrac{30x+30}{120}-\dfrac{24x}{120}=\dfrac{20x}{120}\)
\(30x+30-24x=20x\)
\(30x-24x-20x=30\)
\(-24x=30\)
\(x=\dfrac{-5}{4}\)
\(\text{Vậy S}\left\{\dfrac{-5}{4}\right\}\)
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