\(\dfrac{x}{x-2}=\dfrac{2x}{2x-1}\left(ĐKXĐ:x\ne2;x\ne\dfrac{1}{2}\right)\)
\(\Leftrightarrow\dfrac{x\left(2x-1\right)}{\left(x-2\right)\left(2x-1\right)}=\dfrac{2x\left(x-2\right)}{\left(x-2\right)\left(2x-1\right)}\)
\(\Rightarrow2x^2-x=2x^2-2x\)
\(\Leftrightarrow-x=-2x\)
\(\Leftrightarrow x=0\left(nhận\right)\)
-Vậy \(S=\left\{0\right\}\)