a: Khi x=3 thì \(A=\dfrac{2\cdot3}{3-1}=3\)
b: \(B=\dfrac{x^2-2x-x^2-8+3x+6}{\left(x-2\right)\left(x+2\right)}=\dfrac{x+2}{\left(x-2\right)\left(x+2\right)}=\dfrac{1}{x+2}\)
c: A*B=1
=>\(\dfrac{2x}{x-1}\cdot\dfrac{1}{x+2}=1\)
=>x^2+x-2=2x
=>x^2-x-2=0
=>(x-2)(x+1)=0
=>x=2(loại) hoặc x=-1(nhận)