a: =>4x-8x=-10-14
=>-4x=-24
hay x=6
b: \(\Leftrightarrow\left(x-3\right)\left(3x+2-x-3\right)=0\)
\(\Leftrightarrow\left(x-3\right)\left(2x-1\right)=0\)
hay \(x\in\left\{3;\dfrac{1}{2}\right\}\)
c: \(\Leftrightarrow x-2-5x-5=x^2-6x-7\)
\(\Leftrightarrow x^2-6x-7=-4x-7\)
\(\Leftrightarrow x^2-2x=0\)
=>x(x-2)=0
=>x=0(nhận) hoặc x=2(loại)