a: \(\Leftrightarrow\left(3a-1\right)\left(a+3\right)+\left(a-3\right)\left(3a+1\right)=2\left(a+3\right)\left(3a+1\right)\)
\(\Leftrightarrow3a^2+9a-a-3+3a^2+a-9a-3=2\left(3a^2+4a+1\right)\)
\(\Leftrightarrow6a^2-6=6a^2+8a+2\)
=>8a+2=-6
=>8a=-8
hay a=-1(nhận)
b: \(\Leftrightarrow\dfrac{10}{3}-\dfrac{3a-1}{4\left(a+3\right)}-\dfrac{7a+2}{6\left(a+3\right)}=2\)
\(\Leftrightarrow\dfrac{40\left(a+3\right)}{12\left(a+3\right)}-\dfrac{3\left(3a-1\right)}{12\left(a+3\right)}-\dfrac{14a+4}{12\left(a+3\right)}=2\)
\(\Leftrightarrow40a+120-9a+3-14a-4=24\left(a+3\right)\)
\(\Leftrightarrow17a+119-24a-72=0\)
=>-7a+47=0
hay a=47/7(nhận)
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