a, \(3x-3=5\Leftrightarrow x=\dfrac{8}{3}\)
b, \(3x+3-2x=3\Leftrightarrow x=0\)
c, \(\left(x+5\right)\left(x-5\right)-\left(x+5\right)\left(2x+1\right)=0\Leftrightarrow\left(x+5\right)\left(x-5-2x-1\right)=0\)
\(\Leftrightarrow\left(x+5\right)\left(-x-6\right)=0\Leftrightarrow x=-5;x=-6\)
d, đk : x khác -1 ; 1
\(\Rightarrow x^2-3x+2-x^2-x=6-x\Leftrightarrow-4x+2=6-x\Leftrightarrow-3x=4\Leftrightarrow x=-\dfrac{4}{3}\left(tm\right)\)
a: =>3(x-1)=5
=>x-1=5/3
hay x=8/3
b: \(\Leftrightarrow3\left(x+1\right)-2x=3\)
=>x+3=3
hay x=0
c: \(\Leftrightarrow\left(x+5\right)\left(x-5\right)-\left(x+5\right)\left(2x+1\right)=0\)
\(\Leftrightarrow\left(x+5\right)\left(-x-6\right)=0\)
=>x=-5 hoặc x=-6
d: \(\Leftrightarrow x^2-3x+2-x^2-x=6-x\)
=>-4x+2=6-x
=>-3x=4
hay x=-4/3(nhận)