Xét \(\Delta ABC:\)
\(DE//BC\left(gt\right).\)
\(\Rightarrow\dfrac{AD}{DB}=\dfrac{AE}{EC}\left(Talet\right).\)
\(Thay:\) \(\dfrac{4}{2}=\dfrac{6,5}{x}.\Rightarrow x=\dfrac{13}{4}.\)
ta có: DE // BC
=> \(\dfrac{AD}{BD}=\dfrac{AE}{EC}\)
<=> \(\dfrac{4}{2}=\dfrac{6,5}{x}\)
<=> x= 6,5 . 2 =13