\(a,\left(3x-1\right)\left(x+3\right)=\left(2-x\right)\left(5-3x\right)\\ \Rightarrow3x^2-x+9x-3=10-5x-6x+3x^2\\ \Rightarrow3x^2+8x-3=3x^2-11x+10\\ \Rightarrow3x^2+8x-3-3x^2+11x-10=0\\ \Rightarrow19x-13=0\\ \Rightarrow x=\dfrac{13}{19}\)
\(b,\left(x+5\right)\left(2x-1\right)=\left(2x-3\right)\left(x+1\right)\\ \Rightarrow2x^2+10x-x-5=2x^2-3x+2x-3\\ \Rightarrow2x^2+9x-5=2x^2-x-3\\ \Rightarrow2x^2+9x-5-2x^2+x+3=0\\ \Rightarrow10x-2=0\\ \Rightarrow x=\dfrac{1}{5}\)
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