a: \(\Leftrightarrow x^2-4x+3=2x-2+x^2-8x+15\)
=>-4x+3=-6x+13
=>2x=10
hay x=5(nhận)
b: \(\Leftrightarrow x^2+3x+x^2+x-2x-2=2x^2+2x\)
=>-2=0(vô lý)
c: \(\Leftrightarrow x^2-8x+12=x^2-4x\)
=>-8x+4x=-12
=>-4x=-12
hay x=3(nhận)
d: \(\Leftrightarrow x^2-3x+2+\left(2x-5\right)\left(x-1\right)-\left(3x-5\right)\left(x-2\right)=0\)
\(\Leftrightarrow x^2-3x+2+2x^2-2x-5x+5-\left(3x^2-6x-5x+10\right)=0\)
\(\Leftrightarrow3x^2-10x+7-3x^2+11x-10=0\)
=>x=3(nhận)