Question

Answer 1

\(\dfrac{2x-1}{x+3}=\dfrac{-3}{4}\\ \Rightarrow4\left(2x-1\right)=-3\left(x+3\right)\\ \Rightarrow8x-4=-3x-9\\ \Rightarrow8x-4+3x+9=0\\ \Rightarrow11x+5=0\\ \Rightarrow11x=-5\\ \Rightarrow x=\dfrac{-5}{11}\)

Answer 2

=>8x-4=-3x-9

=>11x=-5

hay x=-5/11