Câu 16: D
II: Tự luận
Bài 1:
a: \(=x^2-5x+x^2-9=2x^2-5x-9\)
b: \(=\dfrac{x}{2\left(x-1\right)}+\dfrac{x-2}{\left(x-1\right)\left(x+1\right)}-\dfrac{5}{2\left(x+1\right)}\)
\(=\dfrac{x^2+x+2x-4-5x+5}{2\left(x-1\right)\left(x+1\right)}=\dfrac{x^2-2x+1}{2\left(x-1\right)\left(x+1\right)}=\dfrac{x-1}{2\left(x+1\right)}\)