Question

Answer 1

\(\dfrac{x}{3}=\dfrac{y}{5}=\dfrac{x+y}{3+5}=\dfrac{16}{8}=2\\ \Rightarrow\left\{{}\begin{matrix}x=3.2=6\\y=5.2=10\end{matrix}\right.\)

Answer 2

Ta có:

x/3-x/5=0

5x/15-3y/15=0

5x-3y/15=0

=>5x-3y=0

mà x+y=16

<=>x=6

  y=10

Answer 3

\(\dfrac{x}{3}=\dfrac{y}{5}\text{ và }x+y=16\)

\(\text{Áp dụng tính chất dãy tỉ số bằng nhau:}\)

\(\dfrac{x}{3}=\dfrac{y}{5}=\dfrac{x+y}{3+5}=\dfrac{16}{8}=2\)

\(\Rightarrow x=2.3=6\)

\(y=2.5=10\)