Question

Answer 1

\(VT=\left|3x+4\right|+\left|1-3x\right|\ge\left|3x+4+1-3x\right|=5\\ VP\le\dfrac{20}{3\cdot0+4}=5\\ \Rightarrow VT\ge5\ge VP\)

Dấu \("="\Leftrightarrow\left\{{}\begin{matrix}\left(3x+4\right)\left(1-3x\right)\ge0\\x+1=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}-\dfrac{4}{3}\le x\le\dfrac{1}{3}\\x=-1\end{matrix}\right.\Leftrightarrow x=-1\)