Bài 2:
c: \(=\left(x^2-1\right)\left(x^2+1\right)-4x\left(x+1\right)\)
\(=\left(x+1\right)\left[\left(x-1\right)\left(x^2+1\right)-4x\right]\)
Đúng 1
Bình luận (0)
Bài 2:
c: \(=\left(x^2-1\right)\left(x^2+1\right)-4x\left(x+1\right)\)
\(=\left(x+1\right)\left[\left(x-1\right)\left(x^2+1\right)-4x\right]\)