Question

Answer 1

Ghi các bước càng tốt ạ e cảm ơn.

 

Answer 2

a) \(\dfrac{5}{2x^2y}+\dfrac{3}{5xy^2}-\dfrac{x}{y^3}=\dfrac{25y^2}{10x^2y^3}+\dfrac{6xy}{10x^2y^3}-\dfrac{10xy^3}{10x^2y^3}=\dfrac{25y^2+6xy-10xy^3}{10x^2y^3}=\dfrac{y\left(25y+6x-10xy^2\right)}{10x^2y^3}=\dfrac{25+6x-10xy^2}{10x^2y^2}\)

Answer 3

d: \(=\dfrac{2x-3+4x+6-18}{\left(2x-3\right)\left(2x+3\right)}=\dfrac{6x-9}{\left(2x-3\right)\left(2x+3\right)}=\dfrac{3}{2x+3}\)