\(\dfrac{x}{2}=\dfrac{y}{3} \Rightarrow\dfrac{x}{8}=\dfrac{y}{12};\dfrac{y}{4}=\dfrac{z}{5}\Rightarrow\dfrac{y}{12}=\dfrac{z}{15}\\ \Rightarrow\dfrac{x}{8}=\dfrac{y}{12}=\dfrac{z}{15}\)
Áp dụng t/c dtsbn ta có:
\(\dfrac{x}{8}=\dfrac{y}{12}=\dfrac{z}{15}=\dfrac{x+y-z}{8+12-15}=\dfrac{10}{5}=2\)
\(\dfrac{x}{8}=2\Rightarrow x=16\\ \dfrac{y}{12}=2\Rightarrow y=24\\ \dfrac{z}{15}=2\Rightarrow z=30\)
ta có:
\(\dfrac{x}{2.4}=\dfrac{y}{3.4};\dfrac{y}{4.3}=\dfrac{z}{3.5}\)
=>\(\dfrac{x}{8}=\dfrac{y}{12};\dfrac{y}{12}=\dfrac{z}{15}\\ \dfrac{x}{8}=\dfrac{y}{12}=\dfrac{z}{15}\)
áp dụng tính chất dãy tỉ số bằng nhau,ta được
\(\dfrac{x}{8}=\dfrac{y}{12}=\dfrac{z}{15}=\dfrac{x+y-z}{8+12-15}=\dfrac{10}{5}=2\\ \dfrac{x}{8}=2\\ x=16\\ \dfrac{y}{12}=2\\ y=24\\ \dfrac{z}{15}=2\\ z=30\)
