\(R_{tđ}=R_1+R_2=6+9=15\left(\Omega\right)\)
\(I=I_1=I_2=\dfrac{U}{R_{tđ}}=\dfrac{7,2}{15}=0,48\left(A\right)\)
\(\left\{{}\begin{matrix}U_1=I_1.R_1=0,48.6=2,88\left(V\right)\\U_2=I_2.R_2=9.0,48=4,32\left(V\right)\end{matrix}\right.\)
\(\left\{{}\begin{matrix}P_1=U_1.I_1=2,88.0,48=1,3824\left(W\right)\\P_2=U_2.I_2=4,32.0,48=2,0736\left(W\right)\end{matrix}\right.\)
a. Bạn tự vẽ sơ đồ mạch điện nhé!
b. \(R=R1+R2=6+9=15\Omega\)
c. \(I=I1=I2=\dfrac{U}{R}=\dfrac{7,2}{15}=0,48A\left(R1ntR2\right)\)
\(\Rightarrow\left\{{}\begin{matrix}U1=I1\cdot R1=0,48\cdot6=2,88V\\U2=I2\cdot R2=0,48\cdot9=4,32V\end{matrix}\right.\)
d. \(\left\{{}\begin{matrix}P1=U1\cdot I1=2,88\cdot0,48=1,3824\\P2=U2\cdot I2=4,32\cdot0,48=2,0736\end{matrix}\right.\)(W)
