Question

Answer 1

Câu 46: B

Câu 47: \(\frac{2x^4-3x^3+3x-2}{x^2-1}=\frac{2x^4-2x^2-3x^3+3x+2x^2-2}{x^2-1}\)

\(=2x^2-3x+2\)

=>Dư là 0

=>Chọn A

Câu 48: \(\frac{3x^5+5x^4-1}{x^2+x+1}\)

\(=\frac{3x^5+3x^4+3x^3+2x^4+2x^3+2x^2-5x^3-5x^2-5x+3x^2+3x+1}{x^2+x+1}\) +(2x-2)/x^2+x+1

\(=3x^3+2x^2-5x+3+\frac{2x-2}{x^2+x+1}\)

=>Chọn B

Câu 49: C

Câu 50: C

Câu 51:

\(3x^2+6xy^2-3y^2+6x^2y\)

\(=3\left(x^2-y^2\right)+6xy\left(x+y\right)\)

=3(x-y)(x+y)+6xy(x+y)

=3(x+y)(x-y+2xy)

=>Chọn B