Question

Answer 1

Bài 2:

\(a,=\left(x+y\right)-y\left(x+y\right)=\left(1-y\right)\left(x+y\right)\\ b,=x\left(x^2-2x+1-y^2\right)=x\left[\left(x-1\right)^2-y^2\right]=x\left(x-y-1\right)\left(x+y-1\right)\)

Bài 3:

\(a,\Leftrightarrow\left(x+3\right)\left(x+3-x+3\right)=0\Leftrightarrow x=-3\\ b,\Leftrightarrow\left[{}\begin{matrix}5x=0\\x^2+4=0\left(vô.n_0\right)\end{matrix}\right.\Leftrightarrow x=0\)