\(a,=\left(x-2\right)\left(x+2\right)\\ b,=\left(3a-b\right)\left(3a+b\right)\\ c,=\left(x+3\right)\left(x^2-3x+9\right)\\ d,=\left(2x-5\right)\left(4x^2+10x+25\right)\)
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a, x2 - 4 = x2 - 22 =(x - 2).(x + 2)
b, 9a2 - b2 = (3a)2 - b2 = (3a - b).(3a + b)
c, x3 + 27 = x3 + 33 =(x + 3).(x2 - 3x + 9)
d,8b3 - 125 = (2b)3 - 53 = (2b - 5).(4b2 + 10b + 25)
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