\(\sqrt{\dfrac{289}{225}}=\sqrt{\left(\dfrac{17}{15}\right)^2}=\dfrac{17}{15}\)
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\(\sqrt{\dfrac{289}{225}}\)=\(\dfrac{\sqrt{17^2}}{\sqrt{15^2}}\)=\(\sqrt{\left(\dfrac{17}{15}\right)^2}\)=\(\dfrac{17}{15}\)
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