â) \(3x\left(x-2\right)-3x^2=1\\ \Rightarrow3x^2-6x-3x^2=1\\ \Rightarrow-6x=1\\ \Rightarrow x=-\dfrac{1}{6}\)
b) \(x\left(6x-2\right)-3x\left(2x-3\right)=7\\ \Rightarrow6x^2-2x-6x^2+9x=7\\ \Rightarrow7x=7\\ \Rightarrow x=1\)
a) 3x(x-2)-3x²=1
3x²-6x-3x²=1
-6x=1
x=-1/6
b)x(6x-2)-3x(2x-3)=7
6x²-2x-6x²+9x=7
7x=7
x=1
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