Kẻ \(Cz//Ax//By\)
\(\Rightarrow\widehat{zCA}+\widehat{xAC}=180^0\left(trong.cùng.phía\right)\\ \Rightarrow\widehat{zCA}=180^0-50^0=130^0\\ \Rightarrow\widehat{zCB}=\widehat{zCA}-\widehat{BCA}=130^0-30^0=100^0\\ Cz//By\Rightarrow\widehat{zCB}+\widehat{CBy}=180^0\left(trong.cùng.phía\right)\\ \Rightarrow\widehat{CBy}=180^0-100^0=80^0\)