Question

Answer 1

a)
\(x^2-6x+9-x^2-2x=1\)
\(-8x+9=1\)
\(-8x=-8\)
x=1
b)
\(\left(3x+2-2x+5\right)\left(3x+2+2x-5\right)=0\)
\(\left(x+7\right)\left(5x-3\right)=0\)
x+7 = 0 hoặc 5x-3=0
x=-7      hoặc 5x=3
x=-7      hoặc   x=3/5

Answer 2

a)\((x-3)^2-x(x+2)=1\)

\(\Leftrightarrow\)\(x^2-6x+9-x^2-2x-1=0\)

\(\Leftrightarrow\)\(-8x-8=0\)

\(\Leftrightarrow\)\(x=-1\)

b)\((3x+2)^2-(2x-5)^2=0\)

\(\Leftrightarrow\)\(9x^2+12x+4-4x^2+20x-25=0\)

\(\Leftrightarrow\)\(5x^2+32x-21=0\)

\(\Leftrightarrow\)\(\begin{cases} x=-7\\ x=\dfrac{3}{5} \end{cases}\)