1: Ta có: \(-5x\left(x-2\right)+5x^2-3x=-2\)
\(\Leftrightarrow-5x^2+10x+5x^2-3x=-2\)
\(\Leftrightarrow x=-\dfrac{2}{7}\)
2: Ta có: \(8x^2-3-\left(2x-3\right)\left(4x+5\right)=5x\)
\(\Leftrightarrow8x^2-3-8x^2-10x+12x+15-5x=0\)
\(\Leftrightarrow-5x=-12\)
hay \(x=\dfrac{12}{5}\)