\(5x=3z\Rightarrow\dfrac{x}{3}=\dfrac{z}{5};\dfrac{x}{3}=\dfrac{y}{2}\Rightarrow\dfrac{x}{3}=\dfrac{y}{2}=\dfrac{z}{5}\)
Áp dụng t/c dtsbn
\(\dfrac{x}{3}=\dfrac{y}{2}=\dfrac{z}{5}=\dfrac{x+y+z}{2+3+5}=\dfrac{100}{10}=10\\ \Rightarrow\left\{{}\begin{matrix}x=30\\y=20\\z=50\end{matrix}\right.\)
