\(1,\\ a,=2xy\left(x-2y\right)\\ b,=\left(x-y\right)^2-16=\left(x-y-4\right)\left(x-y+4\right)\\ c,=x^2+3x-4x-12=\left(x+3\right)\left(x-4\right)\\ 2,\\ a,\Leftrightarrow4\left(x-5\right)=0\Leftrightarrow x-5=0\Leftrightarrow x=5\\ b,\Leftrightarrow\left(5x-3\right)\left(-2x-2\right)=0\\ \Leftrightarrow-2\left(x+1\right)\left(5x-3\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=-1\\x=\dfrac{3}{5}\end{matrix}\right.\\ c,\Leftrightarrow x^2-1-x^2-2x+8=0\\ \Leftrightarrow-2x=-7\Leftrightarrow x=-\dfrac{7}{2}\)
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