Question

Answer 1

Đặt 3150=a; 6517=b

Ta có: \(L=2\dfrac{1}{a}\cdot\dfrac{3}{b}-\dfrac{1}{\dfrac{a}{3}}\cdot3\dfrac{b-1}{b}+\dfrac{4}{\dfrac{a}{3}}-\dfrac{6}{a\cdot b}\)

\(=\dfrac{2a+1}{a}\cdot\dfrac{3}{b}-\dfrac{3}{a}\cdot\dfrac{4b-1}{b}+\dfrac{12b}{ab}-\dfrac{6}{a\cdot b}\)

\(=\dfrac{6a+3-12b+3+12b-6}{ab}\)

\(=\dfrac{6a}{ab}=\dfrac{6}{b}=\dfrac{6}{6517}\)