Question

Answer 1

làm bài 8 phần a giúp mik với

Answer 2

Bài 8:

a: Ta có: \(A=\left(\dfrac{x-2}{x^2-1}-\dfrac{x+2}{x^2+2x+1}\right)\cdot\dfrac{x^4-2x^2+1}{2}\)

\(=\dfrac{x^2-x-2-x^2-x+2}{\left(x+1\right)^2\cdot\left(x-1\right)}\cdot\dfrac{\left(x-1\right)^2\cdot\left(x+1\right)}{2}\)

\(=-x\left(x-1\right)\)