`(y+2/9) xx 1/5 = 7/15`
`=> y +2/9 = 7/15 : 1/5`
`=> y +2/9 = 7/15 xx 5`
`=> y +2/9= 35/15`
`=> y= 35/15 -2/9`
`=> y= 7/3 -2/9`
`=> y= 21/9-2/9`
`=> y= 19/9`
Vậy `y=19/9`
__
`yxx(12/7 +4/3) = 5/6`
`=> y xx 64/21 = 5/6`
`=> y= 5/6 : 64/21`
`=> y=5/6 xx 21/64`
`=> y=35/128`
Vậy `y= 35/128`
\(\left(y+\dfrac{2}{9}\right)\times\dfrac{1}{5}=\dfrac{7}{15}\)
\(y+\dfrac{2}{9}=\dfrac{7}{15}:\dfrac{1}{5}\)
\(y+\dfrac{2}{9}=\dfrac{7}{15}\times5\)
\(y+\dfrac{2}{9}=\dfrac{7}{3}\)
\(y=\dfrac{7}{3}-\dfrac{2}{9}\)
\(y=\dfrac{21}{9}-\dfrac{2}{9}\)
\(y=\dfrac{19}{9}\)
========================
\(y\times\left(\dfrac{12}{7}+\dfrac{4}{3}\right)=\dfrac{5}{6}\)
\(y\times\left(\dfrac{36}{21}+\dfrac{28}{21}\right)=\dfrac{5}{6}\)
\(y\times\dfrac{64}{21}=\dfrac{5}{6}\)
\(y=\dfrac{5}{6}:\dfrac{64}{21}\)
\(y=\dfrac{5}{6}\times\dfrac{21}{64}\)
\(y=\dfrac{35}{128}\)
1) (y + 2/9) x 1/5 = 7/15
=> (y + 2/9) = (7/15) x 5
=> (y + 2/9) = 7/3
=> y = 7/3 - 2/9
=> y = (21-2)/9
=> y = 19/9
2) y x ( 12/7 + 4/3) = 5/6
=> y x (36/21 + 28/21) = 5/6
=> y x 64/21 = 5/6
=> y = (5/6) x (21/64)
=> y = 35/128
