=> \(\sqrt{2-x}.\sqrt{3-x}+\sqrt{3-x}.\sqrt{5-x}+\sqrt{5-x}.\sqrt{2-x}+5-x=5\)
=> \(\sqrt{3-x}\left(\sqrt{2-x}+\sqrt{5-x}\right)+\sqrt{5-x}\left(\sqrt{2-x}+\sqrt{5-x}\right)=5\)
=> \(\left(\sqrt{5-x}+\sqrt{2-x}\right)\left(\sqrt{5-x}+\sqrt{3-x}\right)=5\)
=> giải tiếp nhé , mình biết lớp 10