Question

Xác định số oxi hóa của các hợp chất và ion sau:

a/ MnO2, HCl , HClO4, MnCl2, MnSO4

b/ CaCO3, HNO3, HClO4, BaCl2, BaSO4

c/ NH4, SO4, NO3, CO3, PO4

Answer 1

a)

MnO₂: Mn⁺⁴, O^-2

HCl: H⁺¹, Cl^-1

HClO₄: H⁺¹, Cl⁺⁷, O^-2

MnCl₂: Mn⁺², Cl^-1

MnSO₄: Mn⁺², S⁺⁶, O^-2

b)

CaCO₃: Ca⁺², C⁺⁴, O^-2

HNO₃: H⁺¹, N⁺⁵, O^-2

HClO₄: H⁺¹, Cl⁺⁷, O^-2

BaCl₂: Ba⁺², Cl^-1

BaSO₄: Ba⁺², S⁺⁶, O^-2

c)

NH₄⁺: N^-3, H⁺¹

SO₄^2-: S⁺⁶, O^-2

NO₃^-: N⁺⁵, O^-2

CO₃^2-: C⁺⁴, O^-2

PO₄^3-: P⁺⁵, O^-2

Answer 2

\(a,MnO_2\left\{{}\begin{matrix}Mn^{4+}\\O^{2-}\end{matrix}\right.\\ HCl\left\{{}\begin{matrix}H^+\\Cl^-\end{matrix}\right.\\ HClO_4\left\{{}\begin{matrix}H^+\\ClO_7^-\end{matrix}\right.\\ MnCl_2\left\{{}\begin{matrix}Mn^{2+}\\Cl^-\end{matrix}\right.\\ MnSO_4\left\{{}\begin{matrix}Mn^{2+}\\SO_4^{2-}\end{matrix}\right.\\ b,CaCO_3\left\{{}\begin{matrix}Ca^{2+}\\CO_3^{2-}\end{matrix}\right.\)

\(HNO_3\left\{{}\begin{matrix}H^+\\NO_3^-\end{matrix}\right.\\ HClO_4\left(đã.làm\right)\\ BaCl_2\left\{{}\begin{matrix}Ba^{2+}\\Cl^-\end{matrix}\right.\\ BaSO_4\left\{{}\begin{matrix}Ba^{2+}\\SO_4^{2-}\end{matrix}\right.\\ c,NH_4^+\\ SO_4^{2-}\\ NO_3^-\\ CO_3^{2-}\\ PO_4^{3-}\)