\(\left(x+2\right)^2=25\\ \Rightarrow\left[{}\begin{matrix}x+2=5\\x+2=-5\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=3\\x=-7\end{matrix}\right.\)
x + 2 = 5 hoặc x + 2 = -5
x = 3 hoặc x = -7
\(\left(x+2\right)^2=25\\ \Rightarrow\left[{}\begin{matrix}x+2=5\\x+2=-5\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=3\\x=-7\end{matrix}\right.\)
x + 2 = 5 hoặc x + 2 = -5
x = 3 hoặc x = -7
25 . 15 + 75 . 45
-10 . 25 - 10 . 75 + 10 . 50
3^x-2 - 2^3 = 19
(2 x - 5)^3 = - 64
2(x-1)^2 + 3 = 35
125 - 25 (x + 3) = 50
2(x+ 3) - 1x = 4
1/ (\(\left(-\dfrac{2}{3}\right)\)\(^2\) x \(\dfrac{-9}{8}\) - 25% x \(\dfrac{-16}{5}\)
2/ -1\(\dfrac{2}{5}\) x 75% + \(\dfrac{-7}{5}\) x 25%
3/ -2\(\dfrac{3}{7}\) x (-125%) + \(\dfrac{-17}{7}\) x 25%
4/ (-2)\(^3\) x (\(\dfrac{3}{4}\) x 0.25) : (2\(\dfrac{1}{4}\) - 1\(\dfrac{1}{6}\))
(x+9)×(x^2-25)=0
(x-7).(16+x^2).(25-x^2)=0
tìm số nguyên x biết (x^2+5):(x^2-25)=0
b,(x^2-5):(x^2-25)<0
Tìm sô´ nguyên x, sao cho:
a,(x^2+5)(x^2-25)=0. ; (x^2-5)(x^2-25)<0
Bài 1: Tính:
a) -25 . 63 - 25 . 3
Bài 2: Tìm x, biết:
c) ( x + 1 )2 = 16 d) ( -38 ) - ( x - 2 ) = -16
96-3(x+8)=42
15.5.(x-25)-225=0
250:x+15=25
36:(x-5)=2^2
[3.(70-x)+5]:2=46
x+2/5x=-3/25 ( x cộng 2 phần 5 x = -3 phần 25
x + (x+1) + (x+2) + (x+3) + .... + 13 + 14 = 14
25 + 24 + 23 +...+ x + (x - 2) + (x – 3) = 25
1 TIM X
a,(x^2+5) nhan (x^2-25)=0
b,(x^2-5)nhan (x^2-25)<0