Question

√(x^2-x+1)=1

 

Answer 1

\(\sqrt{\left(x^2-x+1\right)}=1\)

`=> x^2 - x +1  = 1`

`<=> x^2 - x  + 1 - 1 =0`

`<=> x^2 - x = 0`

`<=> x^2 = x `

\(\Leftrightarrow\left\{{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)

Answer 2

`\sqrt{x^2-x+1}=1`

`<=>x^2-x+1=1`

`<=>x^2-x=0`

`<=>x(x-1)=0`

`<=>[(x=0),(x-1=0):}`

`<=>[(x=0),(x=1):}`

Vậy `S={0;1}`

Answer 3

\(\sqrt{\left(x^2-x+1=1\right)}\)

`<=>` \(x^2-x+1=1\)

`<=>` \(x^2-x=1-1\)

`<=>` \(x^2-x=0\)

`<=>` \(x^2=x\)

`<=>` \(\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)