\(x^2=\dfrac{16}{25}\\ \Rightarrow\left[{}\begin{matrix}x^2=\left(\dfrac{4}{5}\right)^2\\x^2=\left(-\dfrac{4}{5}\right)^2\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{4}{5}\\x=-\dfrac{4}{5}\end{matrix}\right.\)
Bài 1: Tính:
a) -25 . 63 - 25 . 3
Bài 2: Tìm x, biết:
c) ( x + 1 )2 = 16 d) ( -38 ) - ( x - 2 ) = -16
(x^2-16/25).(x^2-16/9)=0. Tìm x
(x+9)×(x^2-25)=0
(x-7).(16+x^2).(25-x^2)=0
Tìm x
a)12 - |x| = 8
b) (x-2/3)2 25/16
c) (3/4-x)3 =25/16
A = {[(5^2 - 3) x 4 - 16 :2 + 6^0] : 3} + 25 - 16 : 2^3
giúp vS
5(x-3) = 70 - 45 =25
x- 3 =25 : 5 = 5 x = 5 +3 =8
x= 5 + 3 = 8
b) 10 + 2 . x = 4^2 =16
2 . x = 16 - 10 = 6
x = 6 : 2 = 3
7x-5=16
8x+2x=25*22
125(28+72)-25(32*4+64)
9x-1=9
x4=16
2x/25=1
3x=9
1/ (\(\left(-\dfrac{2}{3}\right)\)\(^2\) x \(\dfrac{-9}{8}\) - 25% x \(\dfrac{-16}{5}\)
2/ -1\(\dfrac{2}{5}\) x 75% + \(\dfrac{-7}{5}\) x 25%
3/ -2\(\dfrac{3}{7}\) x (-125%) + \(\dfrac{-17}{7}\) x 25%
4/ (-2)\(^3\) x (\(\dfrac{3}{4}\) x 0.25) : (2\(\dfrac{1}{4}\) - 1\(\dfrac{1}{6}\))
Tìm x € Z biết :
A) 23+x=15
B) x–18=-23
C) x+(-4)=16
D) 25–x=-16
E) (-35).x=-210
F) (-2).(15–x)=60
