(x+1)+(x+2)+(x+3)+...+(x+100)=5750
=>(x+x+x+...+x)+(1+2+3+4+....100)=5750
100 số 100 số
=>100x+(100+1)*100:2=5750
=>100x+5050
=>100x=5750-5050
=>100x=700
=>x=700:100
=>x=7
Vậy x=7
(x + 1) + (x + 2) + (x + 3) + ... + (x + 100) = 5750
(x + x + x + ... + x) + (1 + 2 + 3 + .. + 100) = 5750
100x + 5050 = 5750
100x = 5750 - 5050
100x = 700
x = 7
(x + 1) + (x + 2) + (x + 3) + ... + (x + 100) = 5750
=> (x + x + x + ... + x) + (1 + 2 + 3 + ... + 100) = 5750
có 100 số x có 100 số hạng
=> 100x + (1 + 100).100 : 2 = 5750
=> 100x + 101.100 : 2 = 5750
=> 100x + 5050 = 5750
=> 100x = 5750 - 5050
=> 100x = 700
=> x = 700 : 100
=> x = 7
Vậy x = 7
Ta có :
\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+100\right)=5750\)
\(\Leftrightarrow\)\(\left(x+x+x+...+x\right)+\left(1+2+3+...+100\right)=5750\)
Xét dãy 1;2;3;...;100 :
Số số hạng là : \(100-1+1=100\) ( số hạng )
Tổng là : \(\frac{\left(100+1\right).100}{2}=5050\)
Do đó :
\(\left(x+x+x+...+x\right)+\left(1+2+3+...+100\right)=5750\)
\(\Leftrightarrow\)\(100x+5050=5750\)
\(\Leftrightarrow\)\(100x=5750-5050\)
\(\Leftrightarrow\)\(100x=700\)
\(\Leftrightarrow\)\(x=\frac{700}{100}\)
\(\Leftrightarrow\)\(x=7\)
Vậy \(x=7\)
Chúc bạn học tốt ~
\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+.......+\left(x+100\right)=5750\)
\(\left(x+x+x+.........+\right)+\left(1+2+3+...........+100\right)=5750\)
\(100x+5050=5750\)
\(100x=5750-5050\)
\(100x=700\)
\(x=7\)
(x+1)+(x+2)+(x+3)+...+(x+100)=5750
100x+(1+2+3+...+100)=5750
100x+5050=5750
100x=700
x=7
(x+1)+(x+2)+...+(x+100)=5750
x+1+x+2+...+x+100=5750
100x+5050=5750
=>100x=5750-5050=700
=>x=700:100
x=7
Vậy x bằng 7 (^-^)
(x + 1) + (x + 2) + (x + 3) + ... + (x + 100) = 5750
=> (x + x + x + ... + x) + (1 + 2 + 3 + ... + 100) = 5750
có 100 số x có 100 số hạng
=> 100x + [(1 + 100) . 100 : 2] = 5750
=> 100x + [101 . 100 : 2] = 5750
=> 100x + [10100 : 2] = 5750
=> 100x + 5050 = 5750
=> 100x = 5750 - 5050
=> 100x = 700
=> x = 700 : 100
=> x = 7
Vậy x = 7
