Question

(x+1)\(^2\)=4

Answer 1

\(\left(x+1\right)^2=4\)

\(\Leftrightarrow\left[{}\begin{matrix}x+1=2\\x+1=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-3\end{matrix}\right.\)

Vậy: ...

Answer 2

`(x+1)^2 = 4`

`=> (x+1)^2 = (+-2)^2`

`=> x + 1 = 2`hay `x + 1 = -2`

`=> x =  2 - 1` hay `x = -2 - 1`

`=> x = 1` hay `x = -3`

Vậy: `x in {1 ; -3}`

Answer 3

TH1: x + 1 = 2

=> x = 1

TH2: x + 1 = -2

=> x = -3