\(x_1^2+x_2^2=\left(x_1+x_2\right)^2-2x_1x_2\)
\(=\left(\dfrac{7}{2}\right)^2-2.3\)
\(=\dfrac{25}{4}\)
x1^2+x2^2=(x1+x2)^2-2x1x2
=49/4-2*3=49/4-6
=25/4
\(x_1^2+x_2^2=\left(x_1+x_2\right)^2-2x_1x_2=\left(\dfrac{7}{2}\right)^2-3.2=\dfrac{49}{4}-6=\dfrac{25}{4}\)